Given
9 non-credentialed subs and 5 credentialed subs taught in the district.
$1140
6 non-credentialed subs and 5 credentialed subs taught
$900
Procedure
x = subs with no credential
y = subs with credential
Equations
[tex]\begin{gathered} 5x+9y=1140 \\ 5x+6y=900 \end{gathered}[/tex]Solving the system
[tex]\begin{gathered} 5x+9y=1140 \\ - \\ 5x+6y=900 \\ \\ 5x-5x+9y-6y=1140-900 \\ 3y=240 \\ y=\frac{240}{3} \\ y=80 \end{gathered}[/tex]Now, for x
[tex]\begin{gathered} 5x+6y=900 \\ 5x=900-6y \\ x=\frac{900-6y}{5} \\ x=\frac{900-6\cdot80}{5} \\ x=84 \end{gathered}[/tex]