The polygon given is a trapezium
The area of a polygon is given by
[tex]\frac{(a+b)}{2}\text{ x h}[/tex]where
[tex]\begin{gathered} a\text{ and b are parallel the sides} \\ h\text{ is the perpendicular height} \end{gathered}[/tex]From the question given
The parallel sides are 12yd and 16yd
[tex]\begin{gathered} so\text{ that} \\ a=12yd \\ b=16yd \end{gathered}[/tex]and perpendicular height is 6yd
The next step is to substitute the values into the formula to obtain the area
[tex]\begin{gathered} A=\frac{(12+16)}{2}\text{ x 6} \\ \\ A=\frac{28}{2}\text{ x 6} \\ \\ A=\text{ 14 x 6} \\ \\ A=84yd^2 \end{gathered}[/tex]