Question

9. C(x) = 800 + 20x (a) 10 (b) 50 (c) 200

Answer 1

Given:

$c(x)=800+20x$

(a)

Value of function then x is 10.

so:

$\begin{gathered} c(x)=800+20x \\ x=10 \end{gathered}$$\begin{gathered} c(10)=800+20(10) \\ c(10)=800+200 \\ c(10)=1000 \end{gathered}$

(b)

Function at x = 50 then:

$\begin{gathered} c(x)=800+20x \\ x=50 \\ c(50)=800+20(50) \\ c(50)=800+1000 \\ c(50)=1800 \end{gathered}$

(c)

At x = 200.

$\begin{gathered} c(x)=800+20x \\ x=200 \\ c(200)=800+20(200) \\ c(200)=800+4000 \\ c(200)=4800 \end{gathered}$