Step 1
subtract 2x in both sides ( the equation is not affected because we do the same operation on each side)
[tex]\begin{gathered} 2x+3y-2x=12-2x \\ 3y=12-2x \end{gathered}[/tex]Step 2
divide each side by 3
[tex]\begin{gathered} 3y=12-2x \\ \frac{3y}{3}=\frac{12}{3}-\frac{2}{3}x \\ y=\frac{-2}{3}x+4 \end{gathered}[/tex]so, the answer is y= -(2x/3)+4