We have the following:
we must calculate the value of z within that interval as follows
[tex]\frac{x_1-m}{sd}where x1 is 300 and x2 is 350m is the mean 400
sd is the standar deviation 50
replacing:
[tex]\begin{gathered} \frac{300-400}{50}now, with the normal distribution table, we calculate the probabilitythe probability then would be
[tex]0.15866-0.02275=0.13591[/tex]So, the probability is 13.59%