Given: A function y,
[tex]y=2x^2+5x+2[/tex]
Required: To find the zeroes of the given function.
Explanation: For finding the zeroes of the function put y=0 i.e.,
[tex]\begin{gathered} 2x^2+5x+2=0 \\ 2x^2+4x+x+2=0 \\ 2x(x+2)+1(x+2)=0 \\ (2x+1)(x+2)=0 \end{gathered}[/tex]
which gives the value of x as
[tex]\begin{gathered} x=-\frac{1}{2}\text{ and} \\ x=-2 \end{gathered}[/tex]
Final Answer: Option C is correct.
