The equation given is,
[tex]6x²\:+\:5x\:-\:6=\:0[/tex]Solve with quadratic formula
[tex]\begin{gathered} x_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:6\left(-6\right)}}{2\cdot \:6} \\ x_{1,\:2}=\frac{-5\pm \:13}{2\cdot \:6} \\ \mathrm{Separate\:the\:solutions} \\ x_1=\frac{-5+13}{2\cdot \:6},\:x_2=\frac{-5-13}{2\cdot \:6} \\ x=\frac{2}{3},\:x=-\frac{3}{2} \\ \mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:} \\ x=\frac{2}{3},\:x=-\frac{3}{2} \end{gathered}[/tex]Hence,
[tex]x=\frac{2}{3},\:x=-\frac{3}{2}[/tex]
