Given:
The mass of the body X is m = 500 g =0.5 kg
The initial speed of the body X is
[tex]v_{xi}=\text{ 20 m/s}[/tex]The mass of the body Y is m' = 200g = 0.2 kg
The initial speed of the body Y is
[tex]v_{yi}=\text{ 10 m/s}[/tex]The final speed of the body Y is
[tex]v_{yf}=\text{ 25 m/s}[/tex]To find the final speed of the body X.
Explanation:
The final speed of the body X can be calculated as
[tex]\begin{gathered} mv_{xi}+m^{\prime}v_{yi}=mv_{xf}+m^{\prime}v_{yf} \\ v_{xf}=\frac{mv_{xi}+m^{\prime}v_{yi}-m^{\prime}v_{yf}}{m} \\ =\frac{0.5\times20+0.2\times10-0.2\times25}{0.5} \\ =14\text{ m/s} \end{gathered}[/tex]Thus, the speed of the body X after impact is 14 m/s.
