Question

(Figure 1) An amusement park ride consists of airplane-shaped cars attached to steel rods. Each rod has a length of 15m. Assume the rod has no mass, when the ride is operating, it has a maximum angular speed of ω = 8.0rev/min. The cart has a weight of 1900 N. What is the tension on the bar?I understand that T = mg + mrω^2, but I can't figure out how to find r

Answer 1

ANSWER

$3,952.03\text{ }N$

EXPLANATION

Parameters given:

Length of the rod, r = 15 m

Angular speed, ω = 8.0 rev/min = 8.0 * 0.105 rad/s = 0.84 rad/s

Weight of the cart, W = 1900 N

To find the tension on the bar, we have to apply the formula for tension:

$\begin{gathered} T=mg+m\omega^2r \\ \\ T=W+m\omega^2r \end{gathered}$

where m = mass of the cart = 1900/ 9.8 = 193.88 kg

Therefore, the tension on the bar is:

$\begin{gathered} T=1900+(193.88*(0.84)^2*15) \\ \\ T=1900+2052.03 \\ \\ T=3,952.03\text{ }N \end{gathered}$

That is the tension on the bar.