Question

how far horizontally has the car traveled in 15 seconds

Answer 1

Given,

The acceleration of the car,

$a=2.5m/s^2$

The angle of inclination,

$\theta=5.9^o$

Let the distance travelled along inclined be s at time t=15 s

Thus,

$\begin{gathered} s=\frac{1}{2}at^2 \\ \Rightarrow s=\frac{1}{2}\times2.5\times15^2=281.25\text{ m} \end{gathered}$

Along horizontal the distance travelled is

x=scos5.9=281.25cos5.9=279.76 m