To solve the equation
[tex]n^2=32[/tex]we take the square root of both sides to get
[tex]\sqrt[]{n^2}=\sqrt[]{32}[/tex][tex]n=\sqrt[]{32}[/tex]Now,
[tex]\sqrt[]{32}=\sqrt[]{16\cdot2}[/tex][tex]\therefore n=\sqrt[]{16\cdot2}[/tex][tex]n=\sqrt[]{16}\times\sqrt[]{2}[/tex][tex]\boxed{n=4\sqrt[]{2}\text{.}}[/tex]
Which is our answer!
