Question

(2/3×2/3×2/3)+(1/9×1/9)×(8-2)

Answer 1

We have

$\mleft(\frac{2}{3}\times\frac{2}{3}\times\frac{2}{3}\mright)+\mleft(\frac{1}{9}\times\frac{1}{9}\mright)\times\mleft(8-2\mright)​$

First we have to solve the operations inside the parentheses

$(\frac{8}{27})+(\frac{1}{81})(6)$

then we solve the multiplication

$\begin{gathered} (\frac{8}{27})+(\frac{6}{81}) \\ \end{gathered}$

we need to have the same denominator in order to sum fractions

$\frac{(8\times81)+(6\times27)}{27\times81}=\frac{648+162}{2187}=\frac{810}{2187}=\frac{10}{27}$

the expression simplified is 10/27