The given equation of the line is:
[tex]7x+4y=-28[/tex]
It is required to find the x-intercept and the y-intercept.
To find the x-intercept, substitute y=0 into the equation and find x:
[tex]\begin{gathered} 7x+4(0)=-28 \\ \Rightarrow7x=-28 \\ \text{ Divide both sides by }7: \\ \Rightarrow\frac{7x}{7}=\frac{-28}{7} \\ \Rightarrow x=-4 \end{gathered}[/tex]
Hence, the x-intercept is -4.
To find the y-intercept, substitute x=0 into the equation and find y:
[tex]\begin{gathered} 7(0)+4y=-28 \\ \Rightarrow4y=-28 \\ \text{ Divide both sides by }4: \\ \Rightarrow\frac{4y}{4}=\frac{-28}{4} \\ \Rightarrow y=-7 \end{gathered}[/tex]
The y-intercept is -7.
Answers:
x-intercept: -4
y-intercepe: -7
