Question

How many moles are in 9.62 x 10^23 atoms of iron?

Answer 1

Answer:

1.598moles

Explanations:

According to the Avogadro's constant;

1 mole of an atom = 6.02 * 10^23 molecules

If there are 9.62 x 10^23 atoms of iron, the number of moles it contains is expressed as:

$\begin{gathered} mole\text{ of Fe}=\frac{9.62\times10^{23}}{6.02\times10^{23}} \\ moles\text{ of Fe}=\frac{9.62}{6.02} \\ moles\text{ of Fe}=1.598moles \end{gathered}$

Hence the required moles of iron is 1.598moles