solution:
In a fair die, there are 6 possible outcomes;
The probability of obtaining less than 5 is;
[tex]\begin{gathered} P(less\text{ }than\text{ }5)=\frac{n(lessthanfive)}{n(total)} \\ \\ P(less\text{ }than\text{ }5)=\frac{4}{6} \end{gathered}[/tex]Thus, the probability of not less than 5 is;
[tex]\begin{gathered} P(not\text{ }less\text{ }than\text{ }5)=1-\frac{4}{6} \\ \\ P(not\text{ }less\text{ }than\text{ }5)=\frac{2}{6} \\ \\ P(not\text{ }less\text{ }than\text{ }5)=\frac{1}{3} \end{gathered}[/tex]ANSWER:
[tex]\frac{1}{3}[/tex]