Question

22 percent of skittles are pruple, 22 percent are orange, 21 percent are yellow, 18 percent red, 17 percent green. Find the following probabilities and write them as decimalsP(next two are orange)P(next two has at least one green)

Answer 1

Solution:

Given the following:

Purple skittles = 22%

Orange skittles = 22%

Yellow skittles = 21%

Red skittles = 18%

Green skittles = 17%

(a) P(next two are orange) = p(first is orange and second is orange)

$=\frac{22}{100}\text{ x }\frac{22}{100}=\text{ 0.0484}$

P(next two are orange) = 0.0484

(b)P(next two has at least one green):

P(next two has at least one green)= 1 - p( first is not green and second is not green)

percentage of not green = 22 + 22 + 21 + 18 = 83

p(not green) = 83/100 = 0.83

$\begin{gathered} p(first\text{ not green and second is not green\rparen = 0.83 x 0.83 = 0.6889} \\ \end{gathered}$

P(next two has at least one green)= 1 - 0.6889 = 0.3111