Respuesta :

EXPLANATION

Subtracting au/2 to both sides:

[tex]-\frac{bv}{3}>10-\frac{au}{2}[/tex]

Multiplying both sides by -1 and reversing:

[tex]\frac{bv}{3}<-10+\frac{au}{2}[/tex]

Multiplying both sides by 3:

[tex]bv<-30+\frac{3au}{2}[/tex]

Taking 2 as a common factor:

[tex]bv<\frac{-60+3au}{2}[/tex]

Dividing both sides by b:

[tex]v<\frac{-60+3au}{2b}[/tex]

Rearranging terms:

[tex]v<\frac{3au-60}{2b}[/tex]

The appropiate inequality is the first option.

RELAXING NOICE
Relax