Question

What is the component form of a vector with magnitude 8 and direction 120°120°?

Answer 1

Given:

A vector with a magnitude 8 and a direction 120°

The component form of the vector will be as follows:

$\begin{gathered} x-component=8*cos(120)=8*(-\frac{1}{2})=-4 \\ y-component=8*sin(120)=8*(\frac{\sqrt{3}}{2})=4\sqrt{3} \end{gathered}$

So, the answer will be, the given vector will be as follows:

$v=<-4,4\sqrt{3}>$