Hi, I was absent today in class and I really need help with question 4I will be much appreciated if you show work and the step so I can be more understanding thank you!

Hi I was absent today in class and I really need help with question 4I will be much appreciated if you show work and the step so I can be more understanding tha class=

Respuesta :

4.

[tex]4.83^x=29.1[/tex]

We can use logarithms to solve this problem.

Start by taking the common logarithm of each side:

[tex]\log (4.83^x)=\log (29.1)[/tex]

Apply the power property of logarithms:

[tex]x\cdot\log (4.83)=\log (29.1)[/tex]

And solve for x:

[tex]\begin{gathered} x=\frac{\log 29.1}{\log 4.83}=\frac{1.46}{0.68} \\ x=2.14 \end{gathered}[/tex]

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