Find the area of the cross section through the center of the sphere. Use 3.14 for pi.

The cross section is a circle with radius 5in
[tex]\begin{gathered} \text{area = }\pi\times r^2 \\ \text{since r=5in.} \\ \text{Then} \\ \text{area =3.14}\times5\times5=78.5\text{ square inches} \end{gathered}[/tex]