The volume of the box-shaped a cuboid is
[tex]V=l\times w\times h[/tex]l is the length
w is the width
h is the height
From the given figure
The volume of the box is 93 1/2 ft^3
V = 93 1/2
The width is 2 ft
w = 2
The height is 5 1/2 ft
h = 5 1/2
Substitute them in the rule above
[tex]\begin{gathered} 93\frac{1}{2}=l\times2\times5\frac{1}{2} \\ \frac{93\times2+1}{2}=l\times2\times\frac{5\times2+1}{2} \\ \frac{187}{2}=l\times2\times\frac{11}{2} \\ \frac{187}{2}=l\times11 \end{gathered}[/tex]Multiply both sides by 2 to remove the denominator
[tex]187=22l[/tex]Divide both sides by 22 to find l
[tex]\begin{gathered} \frac{187}{22}=\frac{22l}{22} \\ 8\frac{1}{2}=l \end{gathered}[/tex]The length of the box is 8 1/2 ft
The answer is B