Respuesta :

Given polynomial,

[tex]x^3-3x+2[/tex]

One of its factors is (x+2).

Now, the polynomial is

[tex]x^2-2x+1[/tex]

The factors of the above polynomial are

[tex]\begin{gathered} x^2-2x+1 \\ x^2-x-x+1 \\ x(x-1)-1(x-1) \\ (x-1)(x-1) \end{gathered}[/tex]

The remaining factors of the polynomial are (x-1) (x-1).

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