Given:
[tex]\begin{gathered} b=14\text{ in} \\ h_1=8cm \\ h_2=19.5cm \end{gathered}[/tex][tex]\text{Volume of a triangular pyramid=}\frac{1}{3}(\frac{1}{2}bh_1)h_2[/tex][tex]\begin{gathered} 1\text{ in =2.54 }cm \\ b\text{=14}\times2.54 \\ b\text{=}35.56\text{ cm} \end{gathered}[/tex][tex]\begin{gathered} \text{Volume of a triangular pyramid}=\frac{1}{3}\times\frac{1}{2}\times35.56\times8\times19.5 \\ =924.56cm^3 \end{gathered}[/tex]
