We will use the formula;
[tex]A\text{ }=\text{ P(1+}\frac{r}{n})^{nt}[/tex]where A is the amount
P is the prncipal also known as the initial amount
r is the rate
t is the time
n is the number of interest pay in a year
A is the amount after t years
From the question;
p = $1000
r = 2.5% = 0.025
t= 21
n = 12
Substitute the values into the formula
[tex]A=1000(1+\frac{0.025}{12})^{12\times21}[/tex]Evaluate:
[tex]A=1000(1.00208333333)^{252}[/tex][tex]A=1000\text{ (1.689}53589855)[/tex]A = $1689.5359
The value of the account will be $1689.5359