Question

Question 9A father is three times as old as his daughter. In 8 years, he willbe 4 more than twice her age. Which equation can be used tofind their present ages?Ax + 8 = 2(3x + 8) + 4C 3x + 8 = 2(x + 8) + 4B2x + 12 = x + 8D3x + 8 = x + 12

Answer 1

We can create a system of equations to solve this problem,

We know that the father is three times as old as his daughter:

Let x be his age

Let y be her age

Then,

x=3y (1)

x+8=2(y+8)+4 (2)

$\begin{gathered} Substitute\text{ 1 in 2} \\ 3y+8=2(y+8)+4 \\ \end{gathered}$

The answer would be 3x+8=2(x+8)+4, it's the same expression, just with and x.