Question

I need help with this could u help me please

Answer 1

Given:

The function is:

$\begin{gathered} (A)f(x)=x+3 \\ \\ (B)f(x)=|x-3| \\ \\ (C)f(x)=(x-3)^2 \\ \\ (D)f(x)=\sqrt{x} \end{gathered}$

Find-:

Choose the parent function

Explanation-:

The function is

(A)

$f(x)=x+3$

The parent function is f(x) = x

So,

$\begin{gathered} f(x)=x+3 \\ \\ \text{ It is not a parent function} \end{gathered}$

(B)

The function is:

$f(x)=|x-3|$

The parent function is f(x) = |x|

So it is not a parent function.

(C)

The function is:

$f(x)=(x-3)^2$

The is similar types of graph that is

$y=x^2$

So the function f(x) = (x-3)² is not a parent function

(D)

The function is

$f(x)=\sqrt{x}$

So, the function f(x) = √x is a parent function.