Let:
C = Total cost for rent the truck
x = Number of miles traveled by the truck
C = 25 + 0.10x
Tom only has $60, therefore:
[tex]\begin{gathered} C\leq60 \\ 25+0.10x\leq60 \\ \text{Solving for x:} \\ \text{Subtract 25 from both sides:} \\ 0.10x\leq60-25 \\ 0.10x\leq35 \\ \text{Divide both sides by 0.10:} \\ x\leq\frac{35}{0.10} \\ x\leq350 \end{gathered}[/tex]He can drive 350 miles at most