8, 15 and 17 (option D)
Explanation:x = 4
y = 1
a = x² - y²
b = 2xy
c = x² + y²
We will substitute for 4 for x and 1 for y in a, b, c respectively:
[tex]\begin{gathered} a=4^2-1^2\text{ } \\ a\text{ = 16 - 1 = 15} \\ \\ b\text{ = 2(4)(1)} \\ b\text{ = 8} \\ \\ c=4^2+1^2 \\ c=16+1\text{ = }17 \end{gathered}[/tex]Hence, the pythagorean triple generated are 8, 15 and 17 (option D)