Answer:
{a,2}
Explanation:
Given the equation:
[tex](x-2)(x-a)=0[/tex]If the product of two terms is zero, then one of the terms or both must be zero.
Thus, we have that:
[tex]\begin{gathered} x-2=0\text{ or }x-a=0 \\ \implies x=2\text{ or }x=a \end{gathered}[/tex]Therefore, the solution set to the equation is:
[tex]\{a,2\}[/tex]