Answer:
D. 3.5
Explanation:
A fair six-sided dice has faces labeled 1,2,3,4,5 and 6.
The probability of each of the faces occurring = 1/6
Thus, the expected value for a fair six-sided dice roll is:
[tex]\begin{gathered} E(X)=\mleft(1\times\frac{1}{6}\mright)+\mleft(2\times\frac{1}{6}\mright)+\mleft(3\times\frac{1}{6}\mright)+\mleft(4\times\frac{1}{6}\mright)+\mleft(5\times\frac{1}{6}\mright)+\mleft(6\times\frac{1}{6}\mright) \\ =\frac{1}{6}+\frac{2}{6}+\frac{3}{6}+\frac{4}{6}+\frac{5}{6}+\frac{6}{6} \\ =\frac{21}{6} \\ =3.5 \end{gathered}[/tex]The expected value for a fair six-sided dice roll is 3.5.
