What is the exact value of sin(csc^-1 (2)), when 0° < A < 180°

We have the expression:
[tex]\sin (\csc ^{-1}(2))[/tex][tex]0When we operate the function, we will get:[tex]\sin (\csc ^{-1}(2))=\frac{1}{2}[/tex]That is, since:
[tex]\csc ^{-1}(2)=\frac{\pi}{6}[/tex]and then:
[tex]\sin (\frac{\pi}{6})=\frac{1}{2}[/tex]