From the information provided, the warehouse space has 8000 sq ft of showroom and workshop. One hal o this would be used which translates to 4000 sq ft. The warehouse has a height of 20 ft.
The cubic vloume of the warehouse is given as follows;
[tex]\begin{gathered} \text{Vol}=l\times w\times h \\ l\times w=4000,h=20 \\ \text{Vol}=4000\times20 \\ \text{Vol}=80000ft^3 \end{gathered}[/tex]The dimensions for each rim is given as
[tex]\begin{gathered} \text{Dimensions}=36\times36\times15 \\ \text{Note that the dimensions for the rims are measured in inches} \\ 12\text{ inches=1 foot. Therefore,} \\ \text{Dimensions}=3\times3\times1.25 \end{gathered}[/tex]The volume of each rim therefore is;
[tex]\begin{gathered} \text{Vol}=3\times3\times1.25 \\ \text{Vol}=11.25ft^3 \end{gathered}[/tex]To determine how many rims would fit into half of the warehouse,
[tex]\begin{gathered} Number\text{ of rims=}\frac{volume\text{ of warehouse}}{\text{volume of rims}} \\ \text{Number of rims=}\frac{80000}{11.25} \\ \text{Number of rims=}7111.11 \\ \text{Number of rims}\approx7,111 \end{gathered}[/tex]If you must have exactly 4 cans in a rim, then
[tex]\begin{gathered} \text{ Number of cans=Number of rims x 4} \\ \text{ Number of cans=7111 x 4} \\ \text{ Number of cans=28,444} \end{gathered}[/tex]