Question

Can someone please help me Part 1 identify three points On the coordinate plane which will represent a triangle that you will Part 2 translate your triangle six units up and three units left. What are the new points of the triangle after its been translated? Part 3 reflect your original triangle across the y-axis. What are the new points of the triangle after its been reflected? Part 4 rotate your original triangle 90’ clockwise what are the new points of triangle after its been rotated Part 5 dilate your original triangle by a scale factor of 1/2 what are the new points of the triangle after its been dilated

Answer 1

Part 1

You have the following triangle in the coodinate plane:

The previous triangle has the following vertices:

A(0,1), B(1,0), C(-1,-1)

Part 2

If the triangle is translated six units upand three units left, it means that you subtract to each x-coordinate 3 units, and you add 6 unit to each y-coordinate.

Then, the coordinates of the new points of the vertices of the triangle are:

A'(0 - 3 , 1 + 6 ) = A'(-3 , 7)

B'(1 - 3 , 0 + 6) = B'(-2 , 6)

C'(-1 - 3 , -1 + 6) = C'(-4 , 5)

Part 3

If you reflec the orignal triangle acroos the y axis, all y coorindates remain the same, and each x-coordinate becomes its opposite number, that is, it is the same number but ith opposite sign, just as follow:

A'(0 , 1)

B'(-1 , 0)

C'(1 , -1)

Part 4

If the triangle is rotated 90 degrees clockwise, the points are transformed in the following way:

P(x,y) => P'(-y,x)

Then, you have;

A'(-1 , 0)

B'(0 , 1)

C'(1 , -1)

Part 5

If the triangle is dilate by a scale factor of 1/2, the new coordinates are the result of multiplying the original coordinates by the scale factor, just as follow:

A'(1/2x0 , 1/2x1) = A'(0 , 1/2)

B'(1/2x1 , 1/2x0) = B'(1/2 , 0)

C'(1/2x(-1) , 1/2x(-1)) = C'(-1/2 , -1/2)