Respuesta :

The figure is composed of a rectangle with a base of 10 mm and a height of 9 mm, and a triangle with a base of 14 - 10 = 4 mm and a height of 9 - 3 = 6 mm.

The area of the rectangle is calculated as follows:

[tex]\begin{gathered} A=\text{base}\cdot\text{height} \\ A_1=10\cdot9=90\operatorname{mm}^2 \end{gathered}[/tex]

The area of the triangle is calculated as follows:

[tex]\begin{gathered} A=\text{base}\cdot\text{height}\cdot\frac{1}{2} \\ A_2=4\cdot6\cdot\frac{1}{2}=12\operatorname{mm}^2 \end{gathered}[/tex]

Therefore, the total area is

[tex]A_1+A_2=90+12=102\operatorname{mm}^2[/tex]

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