The question requires you to place toys in a bin such that each bin contains the same number of toys without mixing them.That means, for each bin, you're going to need to arrange the toys in the order;
[tex]\begin{gathered} \text{Anemones; 2}\times\times2\times3 \\ \text{Limpets; 2}\times7 \\ \text{Snails; 2}\times3\times3 \\ \text{Observe that the only number common to all three toys is 2} \\ \text{You cannot arrange in threes or sevens, only in twos} \\ \text{Hence, for Bin Anemone, you would need }\frac{12}{2}\text{ bins} \\ \text{Bin Anemones=}6\text{ bins} \\ \text{For Bin Limpets you would need }\frac{14}{2}\text{ bins} \\ Limpets=7\text{ bins} \\ \text{For Bin Snails you would need }\frac{18}{2}\text{ bins} \\ \text{Snails}=9\text{ bins} \end{gathered}[/tex]
