Given: The modlled equation below
[tex]f(x)=63+36log(x-5)[/tex]To Determine: The percentage at the age of 12
Solution
[tex]\begin{gathered} f(x)=63+36log(x-5) \\ x=12 \\ f(x)=63+36log(12-5) \\ f(x)=63+36log7 \end{gathered}[/tex][tex]\begin{gathered} f(x)=63+36(0.845098) \\ f(x)=63+30.42 \\ f(x)=93.42 \\ f(x)\approx93.4(nearest-tenth) \end{gathered}[/tex]Hence, a gril has attained 93.4 % of her adult height by age 12