Question

Two factory plants are making TV panels. Yesterday, Plant A produced 8000 panels. One percent of the panels from Plant A and 4% of the panels from Plant Bwere defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 2%?Number of panels produced by Plant B: ?

Answer 1

Answer:number of panels produced by Plant B = 4000

Explanations:

We are told that :

• Plant ,A, produced ,8000, panels

,

• Let ,b, be the number of ,panels produced by plant B

,

• Therefore, total panels =, A+B= 8000+b

The diagram below illustrates the conditions further

From the diagram above, we can deduct that :

1%A + 4% B = 2 % ( A+B)

$\begin{gathered} 80\text{ +0.04 b = }\frac{2}{100}(\text{ 8000 + b )} \\ 80+0.04b\text{ = 160 +0.02b } \\ 0.04b\text{ -0.02 = 160 -80 } \\ 0.02\text{ b = 80 } \\ b\text{ = }\frac{80}{0.02\text{ }} \\ \therefore b\text{ = 4000 panels } \end{gathered}$

• This means that number of panels produced by Plant B = 4000