Question

) A motorcycle traveling at 35 m/s steps and the brakes and comes to rest in 4.5 seconds. How far did it take for the motorcycle to come to rest?

Answer 1

In order to determine the distance the motorcycle traveled before he stops, first calculate the acceleration, by using the following formula:

$a=\frac{v-v_o}{t}$

where,

vo: initial speed = 35m/s

a: acceleration = ?

v: final speed = 0m/s

t: time = 4.5s

replace the previous valuesand simplify:

$a=\frac{0\frac{m}{s}-35\frac{m}{s}}{4.5s}\approx-7.78\frac{m}{s^2}$

As you can notice, the acceleration is negative because the motorcycle is slowing down the speed.

Next, use the following formula:

$x=v_ot+\frac{1}{2}at^2$

replace the values of the parameters and simplify:

$x=(35\frac{m}{s})(4.5s)+\frac{1}{2}(-7.78\frac{m}{s^2})(4.5s)^2\approx78.72m$

Hence, the motorcycle traveled approximately 78.72m before coming to a stop