Notice that the parallelogram has 2 equal sides and one right angle, therefore, the parallelogram is a square.
Then, we have that the diagonals are perpendicular, which gives us the following equation:
[tex]3y-9=90[/tex]
solving for y we get:
[tex]\begin{gathered} 3y-9=90 \\ \Rightarrow3y=90+9=99 \\ \Rightarrow y=\frac{99}{3}=33 \\ y=33 \end{gathered}[/tex]
we also have that each diagonal bisect the angles of the square. Since all the angles are right angles, we have for x and z:
[tex]\begin{gathered} 5x=45\Rightarrow x=\frac{45}{5}=9 \\ 10z=45\Rightarrow z=\frac{45}{10}=\frac{9}{2} \end{gathered}[/tex]
therefore, y = 33, x = 9 and z = 9/2
