Question

3/8 of a number is at most 72

Answer 1

Let

n ----> the number

Remember that "at most" means ---> less than or equal to

so

the inequality that represents this situation is

$\frac{3}{8}n\leq72$

Solve for n

$\begin{gathered} 3n\leqslant72*8 \\ n\leqslant\frac{72\times8}{3} \\ n\leqslant192 \end{gathered}$

The numbers is less than or equal to 192