This also has a part two to this question I just can’t see it yet

The equation of the circle is given by the following formula:
[tex](x-h)^2+y^2=r^2[/tex]When comparing this formula with the given equation it is concluded that 49 is the term for r^2.
Using this information we can find the radius:
[tex]\begin{gathered} r^2=49 \\ r=\sqrt{49} \\ r=7 \end{gathered}[/tex]Also we can conclude that h has a value of 3 and k a value of 0.
The center of the circle is located at (h,k), it means that it is located at (3,0).
r=7
c=(3,0)