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EXPLANATION

Since we have the equation 50°cos 20º - cos 50° sin 20°, we can apply the following relationship:

[tex]\mathrm{Use\:the\:following\:identity}:\quad\sin(A-B)=\sin A\cos B-\cos A\sin B[/tex][tex]Plug\text{ the terms:}[/tex][tex]=\sin(50-20)[/tex][tex]\mathrm{Simplify}[/tex][tex]=\sin30=\frac{1}{2}[/tex]

In conclusion, the solution is sin (30) = 1/2

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