Question

write the point-slope form of the line's equation satisfying the given condition.Then use the point-slope form of the equation to write the slope-inercept form of the equation. slope=5 ,passing through (4,6)

Answer 1

We have that the point-slope form is

$y-y_1=m(x-x_1)$

where (x1,y1) is a point that the line pass through and m is the slope

In our case we have

(4,6)=(x1,y1)

m=5

we substitute the values and we obtain the point-slope form

$y-6=5(x-4)$

then we need to isolate the y in order to have the slope-intercept form

$\begin{gathered} y-6=5x-20 \\ y=5x-20+6 \\ y=5x-14 \end{gathered}$

the slope-intercept form is y=5x-14