Respuesta :

Since we're working on a rectangle, we know that the diagonals intercect right in the middle, and that they're all equal.

This way,

[tex]AC=BD=22[/tex]

And

[tex]AE=BE=DE=CE=\frac{1}{2}AC=11[/tex]

Now, we also know that

[tex]AD=BC=9[/tex]

And using the Pythagorean theorem, we have that:

[tex]AD^2+CD^2=AC^2[/tex]

Solving for CD,

[tex]\begin{gathered} CD=\sqrt[]{AC^2-AD^2} \\ \rightarrow CD=20.07 \end{gathered}[/tex]

And we know that:

[tex]AB=DC=20.07[/tex]

This way, the final answers would be:

[tex]\begin{gathered} AD=9 \\ AC=22 \\ CD=20.07 \\ AB=20.07 \\ BD=22 \\ BC=9 \\ AE=11 \\ BE=11 \\ CE=11 \\ DE=11 \end{gathered}[/tex]

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