In this diagram WQ = AB. One way to prove this is true is to draw a line through B such that BDAC. Then prove △ABC is congruent to △DCB, and use corresponding parts of the two triangles. Explain why △ABC is congruent to △DCB.

Given
[tex]\begin{gathered} WQ=\frac{1}{2}AB \\ BD=AC,BD\parallel AC \end{gathered}[/tex]To explain why △ABC is congruent to △DCB.
Explanation:
It is given that,
d
[tex]\begin{gathered} WQ=\frac{1}{2}AB \\ BD=AC,BD\parallel AC \end{gathered}[/tex]Since
[tex]BD\parallel AC[/tex]Then,
[tex]\angle ACB=\angle DBC[/tex]Also,
[tex]\begin{gathered} BD=AC, \\ BC\text{ is common.} \end{gathered}[/tex]Hence, by SAS ongruence rule △ABC is congruent to △DCB.