Question

A 10.1 kg bowling ball and a 8.4 kg bowling ball rest on a rack 1.25 m apart. What is the gravitational force exerted between them?

Answer 1

Given data:

* The mass of the first bowling ball is 10.1 kg.

* The mass of the second bowling ball is 8.4 kg.

* The distance between the bowling balls is 1.25 m.

Solution:

The gravitational force between the bowling balls is,

$F=\frac{Gm_1m_2}{r^2}$

where G is the graviatational constant, m_1 is the mass of first bowling ball, m_2 is the mass of second bowling ball, and r is the distance between the bowling balls,

$\begin{gathered} F=\frac{6.67\times10^{-11}\times10.1\times8.4}{1.25^2} \\ F=362.16\times10^{-11}\text{ N} \end{gathered}$

Thus, the gravitational force acting between the bowling balls is,

$362.16\times10^{-11}\text{ N}$