SOLUTION:
We are to find the slope of a line that is parallel to the given points (2,3) and (4,-6).
[tex]\text{Slope = }\frac{y_2-y_1}{x_2-x_1}[/tex]Where x 1 = 2, x 2 = 4, y 1 = 3 and y 2 = - 6.
[tex]\text{Slope = }\frac{-6-3}{4-2}=\frac{-9}{2}\text{ = - 4.5}[/tex][tex]\begin{gathered} y-y_1=m(x-x_1) \\ U\sin g\text{ the point (2,3)} \\ x_1=2_{} \\ y_1=\text{ 3} \\ m\text{ = slope = -}\frac{9}{2} \end{gathered}[/tex][tex]undefined[/tex]