Given data:
* The mass of the textbooks is m = 23 kg
* The displacement of the textbooks is d = 75 meters.
* The acceleration of the motion is,
[tex]a=0.75ms^{-2}[/tex]Solution:
According to Newton's second law, the force acting on the textbooks is,
[tex]F=ma[/tex]Substituting the known values,
[tex]\begin{gathered} F=23\times0.75 \\ F=17.25\text{ N} \end{gathered}[/tex]The work done on the textbooks is,
[tex]\begin{gathered} W=Fd \\ W=17.25\times75 \\ W=1293.75\text{ J} \\ W=1.29375\times10^3\text{ J} \\ W\approx1.3\text{ kJ} \end{gathered}[/tex]Thus, the work done on the textbooks is approximately 1.3 kJ.