Question

Dihydrogen dioxide decomposes into oxygen gas and water. How many moles of Dihydrogen dioxide are required to produce 6.38 moles of oxygen?

Answer 1

Answer

12.76 moles H₂O₂

Explanation

Given:

Moles of oxygen produced = 6.38 moles

What to find:

The moles of Dihydrogen dioxide required to produce 6.38 moles of oxygen.

Step-by-step solution:

Step 1: Write the balanced equation for the decomposition reaction.

2H₂O₂ --------> O₂ + 2H₂O

Step 2: Calculate the moles of H₂O₂ required.

From the balanced equation;

2 mol H₂O₂ produced 1 mol O₂

x mol H₂O₂ is required to produce 6.38 mol O₂

Cross multiply and divide both sides by 1 mol O₂.

$x=\frac{6.38mol\text{ }O₂}{1mol\text{ }O₂}\times2mol\text{ }H₂O₂=12.76\text{ }mol\text{ }H₂O₂$

The moles of Dihydrogen dioxide required to produce 6.38 moles of oxygen = 12.76 moles H₂O₂