Hello!
First of all, let's divide the sentences contained in the exercise.
• Victor is 18.
Okay, this information is clear.
• Lolly is 3 times younger than Victor.
We can represent it as:
[tex]\mathrm{Lolly=\dfrac{Victor}{3}}[/tex]As we know the age of Victor, we can replace it and solve:
[tex]\begin{gathered} \mathrm{Lolly=\dfrac{18}{3}} \\ \\ \mathrm{Lolly=}6 \end{gathered}[/tex]• Holly is 6 times older than Lolly.
In the same way, we can represent it as:
[tex]\mathrm{Holly=6}\times\mathrm{Lolly}[/tex]As now we know that Lolly has 6 years, we can replace it too:
[tex]\begin{gathered} \mathrm{Holly=6}\times6 \\ \mathrm{Holly=}36 \end{gathered}[/tex]Victor: 18 years
Lolly: 6 years
Holly: 36 years