Respuesta :

Hello!

First of all, let's divide the sentences contained in the exercise.

• Victor is 18.

Okay, this information is clear.

• Lolly is 3 times younger than Victor.

We can represent it as:

[tex]\mathrm{Lolly=\dfrac{Victor}{3}}[/tex]

As we know the age of Victor, we can replace it and solve:

[tex]\begin{gathered} \mathrm{Lolly=\dfrac{18}{3}} \\ \\ \mathrm{Lolly=}6 \end{gathered}[/tex]

• Holly is 6 times older than Lolly.

In the same way, we can represent it as:

[tex]\mathrm{Holly=6}\times\mathrm{Lolly}[/tex]

As now we know that Lolly has 6 years, we can replace it too:

[tex]\begin{gathered} \mathrm{Holly=6}\times6 \\ \mathrm{Holly=}36 \end{gathered}[/tex]

Answers:

Victor: 18 years

Lolly: 6 years

Holly: 36 years

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